53.Reverse the String According to its Index

53

Problem of the Day:
You are given a string s and an integer k. Your task is to transform the string in the following way:
Split the string into groups of size k, starting from index 0.
For each group: Rotate the group to the left by 1 character (the first character moves to the end).
If the last group has fewer than k characters, still apply the same operation.
Finally, return the new transformed string.



  • Input 1:
    String str1=ZohoCorporations
    k=3
    Output1: hoZoCooprtarnois



  • Input 2:
    String str1=Hellokid
    k=2
    Output2:eHllkodi


Comments

  1. Train Everyday20 September 2025 at 00:13

    class Prob1
    {
    public static void main(String[]args)
    {
    String s = "Zohocorporations"; int k = 25;
    String str = "";
    for(int i = 0;i0 && i%k == 0)
    {
    System.out.print(str);
    str = "";
    }

    str = s.charAt(i) + str;
    }
    if(str.length()>0)
    {
    System.out.println(str);
    }
    }
    }

    ReplyDelete

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